Permutations and Combinations

A permutation is an X-string in which all are distinct.

A combination is a way of selecting several things out of a larger group, where order does not matter.

Permutation with Repetition

The number of n-ary strings of length are

\[ n \cdot n \cdot … \cdot n ~ \text{(k times}) = n^k \]

Permutation without Repetition

The number n-letter words where no letter used more than once are

\[ P(26, n) = \frac{26!}{(26 - n)!} \]

In general,

:= number of permutations of elements chosen from a set of size

\[ P(m, n) = \frac{m!}{(m - n)!} \]

Circular Permutation

The number of ways to arrange distinct objects along a fixed circle is

\[ P_n = (n - 1)! \]

Circular Permutation

Permutations of sets with some indistinguishable objects

If you have total objects and unique objects, call the number of indistinguishable objects of type 1, indistinguishable objects of type 2, … and the number of indistinguishable objects of type , then the number of different permutations of these objects is

\[ {n \choose n_1, n_2, …, n_k} = \frac{n!}{n_1! \cdot n_2! \cdot … \cdot n_k!} \]

Hint: MISSISSIPPI problem. Also known as Multinomial Theorem.

Combination with Repetition

The number of ways to choose a subset of size from an n-set, allowing repetition, are

\[ {n + k - 1 \choose k - 1} \]

Combination without Repetition

The number of ways to choose a subset of size from an n-set are

\[ {n \choose k} = \frac{n!}{k! (n - k)!} \]

Proposition:

\[ {n \choose k} = {n \choose n - k} \hskip2em \forall ~ n, k \geqslant 0, k \leqslant n \]

Distributing distinguishable balls into distinguishable bins

\[ k^n \]

Distributing distinguishable balls into indistinguishable bins

The number of surjections from to is

\[ S(n, k) = \sum_{m=0}^k (-1)^m {k \choose m} (k - m)^n \]

Distributing indistinguishable balls into distinguishable bins

\[ {n + k - 1 \choose k - 1} \]

Distributing indistinguishable balls into indistinguishable bins

The number of integer partitions of an integer that has parts. Further reading: Integer Partition.

Binomial Coefficient

Let and be real numbers with , and are non-zero then

\[ (x + y)^n = \sum_{i = 0}^n {n \choose i} x^i y^{n - i} \]

Written on August 24, 2012